Q. 124.0( 6 Votes )

# Using factor theo

Answer :

Let, f (y) = y3-2y2-29y-42

The factors of the constant term – 42 are Putting y = - 2, we have

f (-2) = (-2)3 – 2 (-2)2 – 29 (-2) - 42

= - 8 – 8 + 58 - 42

= 0

So, (y + 2) is a factor of f (y)

Let us now divide

f (y) = y3-2y2-29y-42 by (y + 2) to get the other factors of f (x)

Using long division method, we get

y3 - 2y2- 29y - 42 = (y + 2) (y2 – 4y – 21)

y2 – 4y - 21 = y2 – 7y + 3y - 21

= y (y – 7) + 3 (y – 7)

= (y – 7) (y + 3)

Hence, y3-2y2-29y-42 = (y + 2) (y - 7) (y + 3)

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