Answer :

It is given that f(x) = x4 – 62x2 + ax + 9

Then, f’(x) = 4x3 – 124x+ a


It is given that function f attains its maximum value on the interval [0, 2] at x = 1.


f’(1) = 0


4 – 124 + a = 0


a = 120


Therefore, the value of a is 120.


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