Q. 11 4.6( 124 Votes )

An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. How far apart will be the two planes afterhours?

Answer :

we know, 

Distance = speed × time

Distance traveled by the plane flying towards north in = 1,000 x  

= 1,500 km

Similarly, distance traveled by the plane flying towards west in = 1,200 x  

= 1,800 km

Let these distances be represented by OA and OB respectively.

Pythagoras Theorem : It states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

Applying Pythagoras theorem,


Distances between planes is 300√61 km 

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