Q. 75.0( 2 Votes )

From the given fi

Answer :

In ΔABC and ΔADB,


A = A {Common}


B = D {90° each}


By the criterion of similar triangle AA which says that


if two angles of one triangle are respectively equal to two angles of another triangle then the two triangles are similar


ΔABC ~ ΔADB …(1)


In ΔABC and ΔBDC,


C = C {Common}


B = D {90° each}


By the criterion of similar triangle AA which says that


if two angles of one triangle are respectively equal to two angles of another triangle then the two triangles are similar


ΔABC ~ ΔBDC …..(2)


From (1) and (2),


ΔBDC ~ ΔADB


Hence, option (B) is wrong.

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