Answer :

In ΔABC and ΔADB,

∠ A = ∠ A {Common}

∠ B = ∠ D {90° each}

By the criterion of similar triangle AA which says that

if two angles of one triangle are respectively equal to two angles of another triangle then the two triangles are similar

ΔABC ~ ΔADB …(1)

In ΔABC and ΔBDC,

∠ C = ∠ C {Common}

∠ B = ∠ D {90° each}

By the criterion of similar triangle AA which says that

if two angles of one triangle are respectively equal to two angles of another triangle then the two triangles are similar

ΔABC ~ ΔBDC …..(2)

From (1) and (2),

ΔBDC ~ ΔADB

Hence, option (B) is wrong.

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