Answer :

Let r be the radius of the sphere and Δr be the error in measuring the radius.

Now, it is given that r = 7m and Δr = 0.02m

We know that volume of sphere (V) =


= (4πr2)Δr

= 4π (72)(0.02)m3

= 3.92π m3

Therefore, the approximate error in calculating its volume is 3.92π m3.

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