Q. 64.8( 8 Votes )
Let r be the radius of the sphere and Δr be the error in measuring the radius.
Now, it is given that r = 7m and Δr = 0.02m
We know that volume of sphere (V) =
= 4π (72)(0.02)m3
= 3.92π m3
Therefore, the approximate error in calculating its volume is 3.92π m3.
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Using differentials, find the approximate values of the following:
(0.007)1/3RD Sharma - Volume 1