Q. 64.5( 11 Votes )

# If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.

Answer :

Let r be the radius of the sphere and Δr be the error in measuring the radius.

Now, it is given that r = 7m and Δr = 0.02m

We know that volume of sphere (V) =

Now,

= (4πr^{2})Δr

= 4π (7^{2})(0.02)m^{3}

= 3.92π m^{3}

Therefore, the approximate error in calculating its volume is 3.92π m^{3}.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

How to find Maxima & Minima?43 mins

Tangent & Normal To A Curve53 mins

Test your knowledge of Tangents & Normals (Quiz)52 mins

Interactive quizz on tangent and normal, maxima and minima43 mins

Interactive quiz on maxima and minima48 mins

Tangents & Normals (Concept Builder Class)55 mins

Application of Biotechnology48 mins

Application of Biotechnology | Concepts - 0256 mins

Application of Biotechnology Part 229 mins

Application of Biotechnology | Concepts - 0160 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

If y = sin x and x changes from to, what is the approximate change in y?

RD Sharma - Volume 1Find the percentage error in calculating the surface area of a cubical box if an error of 1% is made in measuring the lengths of the edges of the cube.

RD Sharma - Volume 1The radius of a sphere shrinks from 10 to 9.8 cm. Find approximately the decrease in its volume.

RD Sharma - Volume 1