Q. 25.0( 1 Vote )

# In Δ ABC, DE is || to BC, meeting AB and AC at D and E.If AD = 3 cm, DB = 2 cm and AE = 2.7 cm, then AC is equal toA. 6.5 cmB. 4.5 cmC. 3.5 cmD. 5.5 cm

Given: DE intersect AB and AC and DE || BC

AD = 3 cm, DB = 2 cm and AE = 2.7 cm

Using Basic Proportionality theorem which states that if a straight line is drawn parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the ratio

Putting the values,

Now, AC = AE + EC = 2.7 +1.8 = 4.5 cm

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