# The areas of two similar triangles are 16 cm2 and 36 cm2 respectively. If the altitude of the first triangle is 3 cm, then the corresponding altitude of the other triangle isA. 6.5 cmB. 6 cmC. 4 cmD. 4.5 cm

Given: ar(ABC) = 16 cm2, ar(DEF) = 36 cm2 and altitude of first triangle = 3 cm

Areas of two similar triangles are in the ratio 16:36 = 4: 9

We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of

their corresponding sides or altitudes

Putting the values

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