Q. 195.0( 2 Votes )

The areas of two

Answer :

Given: ar(ABC) = 16 cm2, ar(DEF) = 36 cm2 and altitude of first triangle = 3 cm


Areas of two similar triangles are in the ratio 16:36 = 4: 9


We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of


their corresponding sides or altitudes



Putting the values



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