# The areas of two

Given: ar(ABC) = 16 cm2, ar(DEF) = 36 cm2 and altitude of first triangle = 3 cm

Areas of two similar triangles are in the ratio 16:36 = 4: 9

We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of

their corresponding sides or altitudes

Putting the values

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