# AB <

Given: AB = 5 cm, AP = 8 cm, and CD = 2 cm

We know that two chords AB and CD intersect at P inside the circle with centre at O.

Then PA× PB = PC× PD.

PB =AP – AB = 8 – 5 =3 cm

Let PD = x then PC = PD + CD = 2 + x

8 × 3 = x (2+x)

2x +x2 =24

x2 + (6–4)x – 24 = 0

(x+6)(x –4) =0

x = 4 and –6

x = –6 is not possible because length is always positive

PD = 4 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

A point</spTamil Nadu Board - Math

In the figure, <sTamil Nadu Board - Math

If the tangTamil Nadu Board - Math

In the figure, ifTamil Nadu Board - Math

AB <Tamil Nadu Board - Math

AB and CD are twoTamil Nadu Board - Math

A lotus is Tamil Nadu Board - Math

A circle toTamil Nadu Board - Math

AB <Tamil Nadu Board - Math