Answer :
(i)
To Prove: Δ ABC ∼ Δ AMP
Given: In ΔABC and ΔAMP,
∠ABC = ∠AMP (Each 90°)
Proof:∠ABC = ∠AMP (Each 90°)
∠A = ∠A (Common)
∴ΔABC ΔAMP (By AA similarity)
Hence, Proved.
(ii) Δ ABC ∼ Δ AMP
Now we get that,
Similarity Theorem - If the lengths of the corresponding sides of two triangles are proportional, then the triangles must be similar. And the converse is also true, so we have
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