Answer :

(i)

**To Prove: Δ ABC ∼ Δ AMP****Given: In ΔABC and ΔAMP,**

**∠ABC = ∠AMP (Each 90°)**

**∠ABC = ∠AMP (Each 90°)**

∠A = ∠A (Common)

∴ΔABC ΔAMP (By AA similarity)

Hence, Proved.

(ii) **Δ ABC ∼ Δ AMP**

Now we get that,

**Similarity Theorem**- If the lengths of the corresponding sides of two triangles are proportional, then the triangles must be

**similar**. And the converse is also true, so we have

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