Answer :

Let, p (x) = 2x3+ax2+3x-5 and q (x) = x3+x2-4x+a be the given polynomials.

The remainders when p (x) and q (x) are divided by (x – 2) and p (2) and q (2) respectively.


By the given condition, we have:


p (2) = q (2)


2 (2)3 + a (2)2 + 3 (2) – 5 = (2)3 + (2)2 – 4 (2) + a


16 + 4a + 6 – 5 = 8 + 4 – 8 + a


3a + 13 = 0


3a = - 13


a =


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