Q. 7 A4.3( 14 Votes )

Show that a

Answer :

Given an = 3+4n

So, a1 = 3+4(1) = 7


a2 = 3+4(2) = 11


a3 = 3+4(3) = 15


as of now a1, a2, a3 have the same common difference (d) = 4


so given one is A.P


The sum of first 15 terms is given by (sn) = [2a + (n-1) d]


= [ 2×7 +(15-1) 4]


= 525


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