Q. 74.5( 249 Votes )

In Fig. 6.38, alt

Answer :

(i) In ΔAEP and ΔCDP,

AEP = CDP (Each 90°)


APE = CPD (Vertically opposite angles)


Hence, by using AA similarity,


ΔAEP ΔCDP


(ii) In ΔABD and ΔCBE,


ADB = CEB (Each 90°)


ABD = CBE (Common)


Hence, by using AA similarity,


ΔABD ΔCBE


(iii) In ΔAEP and ΔADB,


AEP = ADB (Each 90°)


PAE = DAB (Common)


Hence, by using AA similarity,


ΔAEP ΔADB


(iv) In ΔPDC and ΔBEC,


PDC = BEC (Each 90°)


PCD = BCE (Common angle)


Hence, by using AA similarity,


ΔPDC ΔBEC


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