Answer :

Let LMN be an equilateral triangle of side 8 cm

LM = MN = NL = 8 cm. (all sides of an equilateral triangle is equal)

Draw altitude LD which is perpendicular to MN.

Then, D is the mid-point of MN.

∴ MD = ND = 1/2

MN = 8/2 = 4 cm

Now, by Pythagoras theorem

LM^{2} = LD^{2} + MD^{2}

⇒ (8)^{2} = LD^{2} + (4)^{2}

⇒ 64 = LD^{2} + 16

⇒ LD = √48 = 4√3 cm.

Hence, altitude of an equilateral triangle is 4√3 cm.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation