Q. 55.0( 3 Votes )

Answer :

We have n = 50

So,

The cumulative Frequency just greater than is 36 then the median class is 10.75 – 11.25 such that

the lower limit (l) = 10.75

cumulative frequency of the class preceding 10.75 – 11.25 (cf) = 19

frequency of the median class 10.75 – 11.25 = 17,

class size (h) = 0.5

Using the formula,, we have

= 10.75 + 0.176

= 10.93

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