Q. 44.1( 396 Votes )

In Fig. 6.36, <sp

Answer :



To Prove: Δ PQS ∼ Δ TQR

Given: In ΔPQR,

PQR = PRQ

Proof: 

As ∠PQR = ∠PRQ

PQ = PR  [sides opposite to equal angles are equal] (i)

Given,

  

    by (1)


In Δ PQS and Δ TQR, we get

 

Q = Q


Therefore,

By SAS similarity Rule which states that Triangles are similar if two sides in one triangle are in the
same proportion to the corresponding sides in the other, and the included angle are equal. 

Δ PQS ∼ Δ TQR 

Hence, Proved.

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