Q. 34.4( 234 Votes )

In Fig. 6.41, if AB || DE, BAC = 35° and CDE = 53°, find DCE.


Answer :

Given: AB parallel DE, BAC = 35oCDE = 53o


To Find: ∠DCE

According to question,

BAC = CED (Alternate interior angles)

Therefore,

CED = 35o


Now, In Δ DEC,

DCE + CED + CDE = 180o (Sum of the interior angles of the triangle)

DCE + 35o + 53o = 180o

DCE + 88o = 180o

DCE = 92o

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