Find the equation

It is given that

Then, the equation of the tangent at any given point (x, y) is given by,

The equation of the given line is 4x − 2y + 5 = 0

y = 2x +

slope of the line = 2

Now, the tangent to the given curve is parallel to the line 4x − 2y + 5 = 0

if the slope of the tangent = the slope of the line

When x =,

y =

Then, Equation of the tangent passing through the point is given by:

24y – 18 = 48x – 41

48x -24y =23

Therefore, the equation of the required tangent is 48x -24y =23

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