Answer :

It is given that

Then, the equation of the tangent at any given point (x, y) is given by,



The equation of the given line is 4x − 2y + 5 = 0


y = 2x +


slope of the line = 2


Now, the tangent to the given curve is parallel to the line 4x − 2y + 5 = 0


if the slope of the tangent = the slope of the line







When x =,


y =


Then, Equation of the tangent passing through the point is given by:





24y – 18 = 48x – 41


48x -24y =23


Therefore, the equation of the required tangent is 48x -24y =23


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