Q. 24.3( 259 Votes )

In Fig. 6.35, &De

Answer :

From the figure,

We see, DOB is a straight line

DOC + COB = 180°  (angles on a straight line form a supplementary pair)

DOC = 180° - 125°

∠ DOC = 55°

Now, In ΔDOC,

DCO + CDO + DOC = 180°

(Sum of the measures of the angles of a triangle is 180°)

DCO + 70° + 55° = 180°

DCO = 55°

It is given that ΔODC ΔOBA

OAB = OCD (Corresponding angles are equal in similar triangles)


Thus,
OAB = 55°

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses