Answer :

From the figure,

We see, DOB is a straight line

∠ DOC + ∠ COB = 180° (angles on a straight line form a supplementary pair)

∠ DOC = 180° - 125°

**∠ DOC = 55°**

Now, In ΔDOC,

∠ DCO + ∠ CDO + ∠ DOC = 180°

(Sum of the measures of the angles of a triangle is 180°)

∠ DCO + 70° + 55° = 180°

**∠ DCO = 55°**

It is given that ΔODC ΔOBA

∠ OAB = ∠ OCD (Corresponding angles are equal in similar triangles)

Thus, **∠**** OAB = 55°**

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