Q. 183.8( 69 Votes )

# For the curve y =

Answer :

The given curve y = 4x3 – 2x5 Then, the slope of the tangent at the point (x, y) is 12x2 – 10x4

The equation of the tangent at (x,y) is given by,

Y – y = (12x2 – 10x4)(X – x) ………….(1)

When the tangent passes through the origin (0,0), then X =Y=0

Then equation (1) becomes,

-y = (12x2 – 10x4)(– x)

y = (12x3 – 10x5)

Also, we have y = 4x3 – 2x5

(12x3 – 10x5) = 4x3 – 2x5

8x5 – 8x3 = 0

x5 – 2x3 = 0

x3(x2 – 1) = 0

x = 0 , 1

When x = 0 then y = 0

When x = 1 then y = 2

And when x = -1 then y = -2

Therefore, the required points are (0, 0), (1,2) and (-1, -2).

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Find the equationRD Sharma - Volume 1

Find the equationMathematics - Board Papers

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the conditioMathematics - Exemplar