The parking charg

Give that, the parking charges of a car for first two hours is Rs. 50 and Rs. 10 for each subsequent hour.

the extra charges for first two hours apart from Rs. 10 per hour = 50-(10× 2)

= 30

Now, let ‘x’ be no. of hours and ‘y’ be the parking charges.

y = 10x + 30 is the equation.

For graph, we’ll first make the table of solutions by putting some random values of x and thereafter we’ll find corresponding values of y and then we’ll plot these points on graph, join them and extend them in straight line to find the graph.

(Note: equation is linear graph will always be straight line.)

Table of solutions for the given equation-

GRAPH:

(Note: Negative values are taken just to make graph but these values are practically impossible)

(i)Given, x = 3 hr.

From the graph, the corresponding y = 60 hr. (pt. E)

(ii)Given, x = 6 hr.

From the graph, the corresponding y = 90 hr. (pt. F)

(iii)Given, y = Rs. 80

From the graph, the corresponding x = 5 hr. (pt. G)

(where, No. of hours = x ; Parking charges = y)

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