Answer :

Give that, the parking charges of a car for first two hours is Rs. 50 and Rs. 10 for each subsequent hour.

the extra charges for first two hours apart from Rs. 10 per hour = 50-(10× 2)


= 30


Now, let ‘x’ be no. of hours and ‘y’ be the parking charges.


y = 10x + 30 is the equation.


For graph, we’ll first make the table of solutions by putting some random values of x and thereafter we’ll find corresponding values of y and then we’ll plot these points on graph, join them and extend them in straight line to find the graph.


(Note: equation is linear graph will always be straight line.)


Table of solutions for the given equation-



GRAPH:



(Note: Negative values are taken just to make graph but these values are practically impossible)


(i)Given, x = 3 hr.


From the graph, the corresponding y = 60 hr. (pt. E)


(ii)Given, x = 6 hr.


From the graph, the corresponding y = 90 hr. (pt. F)


(iii)Given, y = Rs. 80


From the graph, the corresponding x = 5 hr. (pt. G)


(where, No. of hours = x ; Parking charges = y)


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