Give that, the parking charges of a car for first two hours is Rs. 50 and Rs. 10 for each subsequent hour.
⇒ the extra charges for first two hours apart from Rs. 10 per hour = 50-(10× 2)
Now, let ‘x’ be no. of hours and ‘y’ be the parking charges.
⇒ y = 10x + 30 is the equation.
For graph, we’ll first make the table of solutions by putting some random values of x and thereafter we’ll find corresponding values of y and then we’ll plot these points on graph, join them and extend them in straight line to find the graph.
(Note: ∵ equation is linear graph will always be straight line.)
Table of solutions for the given equation-
(Note: Negative values are taken just to make graph but these values are practically impossible)
(i)Given, x = 3 hr.
From the graph, the corresponding y = 60 hr. (pt. E)
(ii)Given, x = 6 hr.
From the graph, the corresponding y = 90 hr. (pt. F)
(iii)Given, y = Rs. 80
From the graph, the corresponding x = 5 hr. (pt. G)
(where, No. of hours = x ; Parking charges = y)
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