Answer :

It is given that equation of curve is y = x2


On differentiating with respect to x, we get


= 2x



Therefore, the slope of the tangent at (0, 0) is 0.


Then, the equation of the tangent is


y – 0 = 0(x – 0)


y = 0


Then, slope of normal at (0,0)


=


Now, equation of the normal at (0,0)


x = 0


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