Q. 143.5( 4 Votes )

Find the missing

Answer :


Given Median =46


Then, median Class = 40 – 50


the lower limit (l) = 40


cumulative frequency of the class preceding 40 – 50 (cf) = 42 + x


frequency of the median class 40 – 50 = 65,


class size (h) = 10


Total frequencies (n) = 229


So, 150 + x + y = 229


x + y = 229 – 150


x + y = 79 …(i)



Using the formula,,we have





39 = 72.5 – x


x = 33.5


Putting the value of x in eq. (i), we get


33.5 + y = 79


y = 79 – 33.5


y = 45.5


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