Q. 144.1( 7 Votes )

A 15 high tower c

Answer :

Given,

Let,



QR = 15 m (height of tower)


PQ = 24 m (shadow of tower)


At that time RPQ = θ


Again, let YZ = h be a telephone pole and its shadow XY = 16 m.


The same time YXZ = θ


Here, ABC and ∆DEF both are right angles triangles.


In ∆PQR and ∆XYZ,


RPQ = YXZ = θ


Q = Y [each 90°]


∆PQR XYZ [by AAA similarity criterion]


Then,



Hence, the height of the telephone pole is 10 m.


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