Q. 144.1( 7 Votes )

A 15 high tower c

Answer :



QR = 15 m (height of tower)

PQ = 24 m (shadow of tower)

At that time RPQ = θ

Again, let YZ = h be a telephone pole and its shadow XY = 16 m.

The same time YXZ = θ

Here, ABC and ∆DEF both are right angles triangles.

In ∆PQR and ∆XYZ,

RPQ = YXZ = θ

Q = Y [each 90°]

∆PQR XYZ [by AAA similarity criterion]


Hence, the height of the telephone pole is 10 m.

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