Q. 13 B

# Find values of K,

Given: – Vertices of triangle are (– 2,0), (0, 4) and (0, k) and the area of the triangle is 4 sq. units.

Tip: – If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:

Now,

Substituting given value in above formula

Removing modulus

Expanding along R1

[ – 2(4 – k) – 0(0) + 1(0 – 0)] = ±8

– 8 + 2k = ± 8

Taking + ve sign, we get

8 = – 8 + 2k

2k = 16

k = 8

Taking – ve sign, we get

– 8 = 2x – 8

2k = 0

k = 0

Thus k = 0, 8

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Show that the Δ AMathematics - Exemplar

Show that the poiMathematics - Exemplar

If the co-ordinatMathematics - Exemplar

Find the value ofRS Aggarwal - Mathematics

Find the area of RS Aggarwal - Mathematics

Find the value ofRS Aggarwal - Mathematics

Find the value ofRS Aggarwal - Mathematics

The area of a triMathematics - Exemplar

If the points (a,RD Sharma - Volume 1