Q. 13 A3.7( 3 Votes )

Find values of K,

Answer :

Given: – Vertices of triangle are (k, 0), (4, 0) and (0, 2) and area of triangle is 4 sq. units


Tip: – If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:



Now,


Substituting given value in above formula



Removing modulus



Expanding along R1



[k(– 2) – 0(4) + 1(8 – 0)] = ±8


[ – 2k + 8] = ± 8


Taking + ve sign, we get


+ 8 = – 2x + 8


– 2k = 0


k = 0


Taking – ve sign, we get


– 8 = – 2x + 8


– 2x = – 16


x = 8


Thus x = 0, 8


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