Q. 134.2( 238 Votes )

D is a point on t

Answer :

In ΔADC and ΔBAC,



To Prove : CA2 = CB . CD

Given: ADC = BAC 

Proof: Now In ΔADC and ΔBAC,

ADC = BAC 

ACD = BCA (Common angle)

According to AA similarity, if two corresponding angles of two triangles are equal then the triangles are similar

ΔADC ΔBAC (By AA similarity)


We know that corresponding sides of similar triangles are in proportion


Hence in ΔADC and ΔBAC, 





Hence Proved 

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