Q. 124.0( 15 Votes )

Solve the followi

Answer :

Given,


x – 2y 3


Putting value of x = 0 and y = 0 in equation one by one, we get value of


y = -3/2 = -1.5 and x = 3


The required points are (0, -1.5) and (3, 0)


Checking for the origin (0, 0)


0 ≤ 3, this is true.


Hence the solution area would be on the left of the line`s graph


3x + 4y 12,


Putting value of x = 0 and y = 0 in equation one by one, we get value of


y = 3 and x = 4


The required points are ( 0,3) and (4,0)


Checking for the origin (0, 0)


0 ≥ 12 , this is not true


So the solution area would of include the origin and the required solution area would be on the right side of the line`s graph.


x 0 ,


For all the values of y, the value of x would be same in the given inequality, which would be the region above the x axis on the graph.


y 1


For all the values of x, the value of y would be same in the given inequality.


The solution area of the line would be not include origin as 0 ≥ 1 is not true.


The solution area would be on the left side of the line`s graph.


The shaded area in the graph is the required solution area which satisfies all the given inequalities at the same time.


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