Q. 114.7( 15 Votes )

Solve the followi

Answer :

Given 2x + y ≥ 4,


Putting value of x = 0 and y = 0 in equation one by one, we get value of


y = 4 and x =2


The required points are (0, 4) and (2, 0)


Checking for origin (0, 0)


0 ≥ 4, this is not true


Hence the origin doesn’t lies in the solution area of the line`s graph. The solution area would be given by the right side of the line`s graph.


x + y 3,


Putting value of x = 0 and y = 0 in equation one by one, we get value of


y = 3 and x = 3


The required points are (0, 3) and (3, 0)


Checking for the origin (0, 0)


0 ≤ 3, this is true


Hence the solution area would include the origin and hence would be on the left side of the line`s graph.


2x – 3y 6


Putting value of x = 0 and y = 0 in equation one by one, we get value of


y = -2 and x = 3


The required points are (0, -2), (3, 0)


Checking for the origin (0, 0)


0 ≤ 6 this is true


So the origin lies in the solution area and the area would be on the left of the line`s graph.


Hence the shaded area in the graph is the required solution area for the given inequalities.



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