Q. 84.0( 5 Votes )

Answer :

Here, the maximum class frequency is 20, and the class corresponding to this frequency is 40 – 50.

So, the modal class is 40 – 50.

Now, modal class = 40 – 50, lower limit (l) of modal class = 40, class size(h) = 10

frequency (f_{1}) of the modal class = 20

frequency (f_{0}) of class preceding the modal class = 12

frequency (f_{2}) of class succeeding the modal class = 11

Now, let us substitute these values in the formula

= 40 + 4.7

= 44.7

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