Answer :


Here,


In ΔADE and ΔABC


ADE = ABC by corresponding angles (DEBC)


DEA = BCA by corresponding angles (DEBC)


ΔAED ΔACB


Similarly,


ΔAGD ΔAFB (where AF BC)


AF = 3AG ( AB = 3AD which is given) ----(1)


Similarly,


BC = 3×DE ----(2)


{by (1) and (2)}



Area of ΔABC = 9 × Area of ΔADE


( Area of ΔABC = 72 cm2)


Area of ΔADE = 8 cm2


Area of DCEB = Area of ΔABC - Area of ΔADE


Area of DCEB = 72 – 8 = 64cm2


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