Answer :
Given
11thterm = 38
⇒ a + (11-1)d = 38 → 1
16th term = 73
⇒ a + (16-1)d = 73 → 2
By subtracting the both equations we will get ‘d’
(a +10d) – (a+15d) = 38 -73
-5d = -35
d = 7
By substituting “d” in equation 1
a +10d = 38
a + 10×7 = 38
a = -32
a31 = a + (31-1) d
= -32 + 30×7
= 178
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