Q. 64.4( 28 Votes )

The angles of a triangle are arranged in ascending order of their magnitude. If the difference between two consecutive angles is 10°, find the three angles.

Answer :

Given:

Let the angles are :


A = x, B = x + 10, C = x + 20



As we know, using theorem (1), in any triangle, sum of the three interior angles is 180°.


So,


A + B + C = 180°


x + x + 10 + x + 20 = 180°


3x + 30° = 180°


3x = 180° - 30°


3x = 150°


x = 50°


So, the angles are,


A = x = 50°


B = x + 10 = 50° + 10° = 60°


C = x + 20 = 50° + 20° = 70°


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RELATED QUESTIONS :

In a triangle ABC, B = 70°. Find A + C.

Karnataka Board - Mathematics Part I