Answer :

we have,

f (x) = 2x3-3x2+ax+b


Put,


x = 0


f (0) = 2 (0)3 – 3 (0)2 + a (0) + b


= 0 – 0 + 0 + b


= b


x = -1


f (-1) = 2 (-1)3 – 3 (-1)2 + a (-1) + b


= -2 – 3 – a + b


= -5 – a + b


Since, x = 0 and x = -1 are roots of f (x)


f (0) = 0 and f (-1) = 0


b = 0 and -5 – a + b = 0


= a – b = -5


= a – 0 = -5


= a = -5


Therefore, a = -5 and b = 0


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