Q. 4

# Find the interval

Answer :

(a) It is given that function f(x) = 2x2 – 3x

f’(x) = 4x – 3

If f’(x) = 0, then we get, So, the points divides the real line into two disjoint intervals, and  So, in interval , f’(x) = 4x -3 >0

Therefore, the given function (f) is strictly increasing in interval .

(b) It is given that function f(x) = 2x2 – 3x

f’(x) = 4x – 3

If f’(x) = 0, then we get, So, the points divides the real line into two disjoint intervals, and  So, in interval f’(x) = 4x -3 < 0

Therefore, the given function (f) is strictly decreasing in interval .

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