Q. 3 B3.8( 10 Votes )

Find the re

Answer :

Given that a2 = 13 & a4 = 3

a2 = a1 + (2-1)d


13 = a1 + d 1


a4 = a1 + (4-1)d


3 = a1 + 3d 2


By subtracting the both equations


13 – 3 = (a1 + d ) - (a1 + 3d)


10 = -2d


d = -5


By substituting in 1 equations we get a1


13 = a1 + (-5)


18 = a1


a3 = a1 + (3-1)d


= 18 + 2 × (-5)


= 8.


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