Answer :


Applying, C2C2 + C1



Taking, (a + b + c) common,



Applying R2R2 – R1, and R3R3 – R1



Taking, (b – c) and (c – a) common,



= (a + b + c)(b – a)(c – a)(b – c)


So, Δ = (a + b + c)(b – a)(c – a)(b – c)


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Prove the followiMathematics - Board Papers