Q. 35.0( 1 Vote )

In ΔXYZ, the bisector of Y intersects in P.

(1) If XP : PZ = 4 : 5 and YZ = 6.5, find XY.

(2) if XY : YZ = 2 : 3 and XP = 3.8, find PZ and ZX.

Answer :

Given, XP : PZ = 4 : 5

XY : YZ = 2 : 3



In ∆XYZ, the bisector of angle Y intersects ZX in P.


(1)



XY =


XY = 5.2


(2)



PZ =


PZ = 5.7


ZX = PZ + XP


ZX = 5.7 + 3.8


ZX = 9.5


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Basic Proportionality Theorem42 mins
Quiz | Criterion of Similarity of Triangle45 mins
Champ Quiz | Thales Theorem49 mins
NCERT | Strong Your Basics of Triangles39 mins
RD Sharma | Imp. Qs From Triangles41 mins
R.D Sharma | Solve Exercise -4.2 and 4.3FREE Class
How to Ace Maths in NTSE 2020?36 mins
R.D Sharma | Solve Exercise-4.545 mins
NCERT | Basic Proportionality Theorem22 mins
RD Sharma | Imp Qs Discussion- Triangles43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :