# If the vertex angle of an isosceles triangle is 50°, find the other angles.

Given: vertex angle

let A = 55°

in an isosceles triangle opposite angles of opposite sides are equal.

Hence,

Let B = C = x

As we know, using theorem (1), in any triangle, sum of the three interior angles is 180 °.

So,

A + B + C = 180°

50° + x + x = 180°

2x = 180° - 50°

2x = 130°

x = 65°

So, B = C = 65°.

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