Answer :

Here,

In the figure above,

FE is the height of the girl.

DC is the height of the lamp.

CE is the distance traveled by the girl in 4 seconds.

GE is the shadow of the girl after 4 seconds.

We need to find GE.

CE = 4 × 0.6 m

CE = 240 cm

In ΔGFE and ΔGDC

∠EFG = ∠CDG by corresponding angles (DC∥FE)

∠GFE = ∠GDC by corresponding angles (DC∥FE)

∴ ΔGFE ∼ ΔGDC

(∵ ΔGFE ∼ ΔGDC)

⇒ 3×GE = 240 + GE

⇒ 2×GE = 240

⇒ GE = 120 cm

⇒ GE = 1.2 m

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