Q. 16

The sum of

Given,

a4 + a8 = 24;

(a + 3d) + (a + 7d) = 24

2a + 10d = 24 a+5d = 12 1

We have been also given that

a6 + a10 = 44

(a + 5d) + (a + 9d) = 44

2a + 14d = 44 a +7d = 22 2

By subtracting two equations

(a + 5d) - (a + 7d) = 12 – 22

-2d = -10

d = 5

Substitute d in any one of the equation.

a+5d = 12

a + 5×5 = 12

a = 2

The first 3 terms of the series is given by a, a+d, a+2d

2, 2+5, 2+2×5

2, 7, 12

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