Answer :

Given,

a4 + a8 = 24;


(a + 3d) + (a + 7d) = 24


2a + 10d = 24 a+5d = 12 1


We have been also given that


a6 + a10 = 44


(a + 5d) + (a + 9d) = 44


2a + 14d = 44 a +7d = 22 2


By subtracting two equations


(a + 5d) - (a + 7d) = 12 – 22


-2d = -10


d = 5


Substitute d in any one of the equation.


a+5d = 12


a + 5×5 = 12


a = 2


The first 3 terms of the series is given by a, a+d, a+2d


2, 2+5, 2+2×5


2, 7, 12


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