# On which of the f

It is given that f (x) = x100 + sin x –1

Then, f’(x) = 100x99 + cosx

In interval (0,1), cos x >0 and 100x99 > 0

f’(x)>0

Therefore, function f is strictly increasing in interval (0,1).

In interval, cos x < 0 and 100x99 > 0.

Also, 100x99 > cos x

f’(x) > 0 in

Therefore, function f is strictly increasing in interval .

In interval , cos x < 0 and 100x99 > 0.

Also, 100x99 > cos x

f’(x) > 0 on

Therefore, function f is strictly increasing in interval .

Hence, function f is strictly decreasing on none of the intervals.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Show that the altMathematics - Board Papers

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1

Find the intervalRD Sharma - Volume 1