Answer :

We have to find the value of n, so that the nth term in the both series should be equal

63, 65, 67, ….

In the above series

First term (a_{1}) = 63,

Common difference (d_{1}) = 2

3, 10, 17, ….

First term (a_{2}) = 3,

Common difference (d_{2}) = 7

Since value of n^{th} term is equal we equate a_{n} of both the series.

a_{n1} = a_{n2}

a_{1} + (n-1)d_{1} = a_{2} + (n-1)d_{2}

63 + (n-1)2 = 3 + (n-1)7

61 +2n = 7n – 4

5n = 65

n = 13.

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