Q. 114.0( 43 Votes )
Prove that the fu
Answer :
It is given that function f(x) = x2 – x + 1
f’(x) = 2x – 1
If f’(x) = 0, then we get,
⇒ x =
So, the point x = divides the interval (-1,1) into two disjoint intervals,
So, in interval
f’(x) = 2x – 1 < 0
Therefore, the given function (f) is strictly decreasing in interval
So, in interval
f’(x) = 2x -1 > 0
Therefore, the given function (f) is strictly increasing in interval for.
Therefore, f is neither strictly increasing and decreasing in interval (-1,1).
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