Q. 114.0( 43 Votes )

# Prove that the fu

Answer :

It is given that function f(x) = x2 – x + 1

f’(x) = 2x – 1

If f’(x) = 0, then we get,

x = So, the point x = divides the interval (-1,1) into two disjoint intervals, So, in interval f’(x) = 2x – 1 < 0

Therefore, the given function (f) is strictly decreasing in interval So, in interval f’(x) = 2x -1 > 0

Therefore, the given function (f) is strictly increasing in interval for .

Therefore, f is neither strictly increasing and decreasing in interval (-1,1).

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