Q. 105.0( 1 Vote )

The governm

Answer :


To find the Area of ΔEBD.


EF = 1.4 Km


In ΔEBD and ΔEAC


EBD = EAC by alternate angles (BDCA)


EDB = ECA by alternate angles (BDCA)


ΔEBD ΔEAC



( BD = 3, AC = 1)


Similarly,


ΔEBG ΔEAF


---(1)



(by (1))



Area of ΔEBD = 6.3


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