Q. 13.8( 58 Votes )
Show that the function given by f (x) = 3x + 17 is strictly increasing on R.
Answer :
Let x1 and x2 be any two numbers in R.
Then, we have,
x1 < x2
⇒ 3x1 < 3x2
⇒ 3x1 +17 < 3x2 +17
⇒ f(x1) < f(x2)
Therefore, f is strictly increasing on R.
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