Let x1 and x2 be any two numbers in R.Then, we have,x1 < x2⇒ 3x1 < 3x2⇒ 3x1 +17 < 3x2 +17⇒ f(x1) < f(x2)Therefore, f is strictly increasing on R.

Q. 13.7( 104 Votes )

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Answer :

Let x₁ and x₂ be any two numbers in R.

Then, we have,

x₁ < x₂

⇒ 3x₁ < 3x₂

⇒ 3x₁ +17 < 3x₂ +17

⇒ f(x₁) < f(x₂)

Therefore, f is strictly increasing on R.

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