# If f(x) =

We have,

f(x) = 2x3-13x2+17x+12

(i) f(2) = 2 (2)3 – 13 (2)2 + 17 (2) + 12

= (2 * 8) – (13 * 4) + (17 * 2) + 12

= 16 – 52 + 34 + 12

= 10

(ii) f (-3) = 2 (-3)3 – 13 (-3)2 + 17 (-3) + 12

= (2 * -27) – (13 * 9) + (17 * -3) + 12

= -54 – 117 – 51 + 12

= - 210

(iii) f (0) = 2 (0)3 – 13 (0)2 + 17 (0) + 12

= 0 – 0 + 0 + 12

= 12

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