Answer :

Given: A ABC with AD as internal bisector of A, meeting BC at D. and AB = 5.6 cm, AC = 6 cm, DC = 3 cm

Required: The length of BC

Here, In ΔABC AD is the internal bisector of ∠A

∴ By angle bisector theorem

⇒

⇒

∴ BD = 2.8cm

∴ Length of BD = 2.8 cm

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