Answer :

For a series to be in AP, the common difference (d) should be

Equal.

D_{1} = second term – first term = -6 – (-10) = 4

D_{2} = Third term - Second term = -2 – (6) = 4

Since common difference is equal the above series is in AP

The next three terms will be the 5^{th}, 6^{th}, 7^{th}.

5^{th} term will be given by

= a + (5-1)d = a + 4d = -10 + 4(4) = 6

6^{th} term is a + (6-1)d = a + 5d = -10 + 5(4) = 10

7^{th} term is a + (7-1)d = a + 6d = -10 + 6(4) = 14

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