Q. 45.0( 2 Votes )

# Δ PQR ~ ΔDEF for the correspondence PQR ↔ EDF. If PQ + QR = 15, DE + DF = 10 and PR = 6, find EF.

Answer :

Given, PQR and DEF are similar for the correspondence PQR EDF.

PQ + QR = 15 and DE + DF = 10

PR = 6

If the correspondence PQRDEF is a similarity.

Hence,

And

From these above two equations

EF

EF = 4

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