Q. 314.0( 32 Votes )

Prove the following trigonometric identities:


Answer :

Taking RHS

tan6θ + 3tan2θsec2θ + 1

= (sec2θ - 1)3 + 3(sec2θ - 1)sec2θ + 1                  [As, tan2θ = sec2θ - 1]

= (sec6θ - 1 - 3sec4θ + 3sec2θ) + (3sec4θ - 3sec2θ) + 1              [(a + b)3 = a3 - b3 - 3a2b + 3ab2]

= sec6θ
= LHS
Hence Proved.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trigonometric Identities33 mins
Champ Quiz | Trigonometric Identities33 mins
NCERT | Trigonometric Identities52 mins
Trigonometric Identities44 mins
Solving NCERT Questions on Trigonometric Identities56 mins
Algebraic Identities48 mins
Quiz | Practice Important Questions on Trigonometrical Identities46 mins
Quiz | Task on Trigonometric Ratios46 mins
Trick to learn all Trigonometric Formulae28 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses